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12221111000122 = 26110555500061
BaseRepresentation
bin1011000111010111001011…
…1110101101110000111010
31121021022211020102201012021
42301311302332231300322
53100212313404000442
641554144554105054
72400642344342563
oct261656276556072
947238736381167
1012221111000122
113991a42612942
12145464941b18a
136a85a46191bb
1430370d74916a
15162d7491ae67
hexb1d72fadc3a

12221111000122 has 4 divisors (see below), whose sum is σ = 18331666500186. Its totient is φ = 6110555500060.

The previous prime is 12221111000107. The next prime is 12221111000123. The reversal of 12221111000122 is 22100011112221.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11896918554481 + 324192445641 = 3449191^2 + 569379^2 .

It is a junction number, because it is equal to n+sod(n) for n = 12221111000096 and 12221111000105.

It is not an unprimeable number, because it can be changed into a prime (12221111000123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3055277750029 + ... + 3055277750032.

Almost surely, 212221111000122 is an apocalyptic number.

12221111000122 is a deficient number, since it is larger than the sum of its proper divisors (6110555500064).

12221111000122 is an equidigital number, since it uses as much as digits as its factorization.

12221111000122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6110555500063.

The product of its (nonzero) digits is 32, while the sum is 16.

Adding to 12221111000122 its reverse (22100011112221), we get a palindrome (34321122112343).

The spelling of 12221111000122 in words is "twelve trillion, two hundred twenty-one billion, one hundred eleven million, one hundred twenty-two", and thus it is an aban number.

Divisors: 1 2 6110555500061 12221111000122