Base | Representation |
---|---|
bin | 11011110010011010111111… |
… | …111110010011001001010011 |
3 | 121000201101002202102001210012 |
4 | 123302122333332103021103 |
5 | 112004311111334014422 |
6 | 1111531304025425135 |
7 | 34512353513613602 |
oct | 3362327776231123 |
9 | 530641082361705 |
10 | 122212220219987 |
11 | 35a38a03280357 |
12 | 1185966933b1ab |
13 | 532674195b5c1 |
14 | 2227162985a39 |
15 | e1e0488284e2 |
hex | 6f26bff93253 |
122212220219987 has 2 divisors, whose sum is σ = 122212220219988. Its totient is φ = 122212220219986.
The previous prime is 122212220219909. The next prime is 122212220220133. The reversal of 122212220219987 is 789912022212221.
It is a weak prime.
It is an emirp because it is prime and its reverse (789912022212221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122212220219987 - 220 = 122212219171411 is a prime.
It is not a weakly prime, because it can be changed into another prime (122212226219987) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61106110109993 + 61106110109994.
It is an arithmetic number, because the mean of its divisors is an integer number (61106110109994).
Almost surely, 2122212220219987 is an apocalyptic number.
122212220219987 is a deficient number, since it is larger than the sum of its proper divisors (1).
122212220219987 is an equidigital number, since it uses as much as digits as its factorization.
122212220219987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 50.
The spelling of 122212220219987 in words is "one hundred twenty-two trillion, two hundred twelve billion, two hundred twenty million, two hundred nineteen thousand, nine hundred eighty-seven".
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