Base | Representation |
---|---|
bin | 10001110010001100101… |
… | …001101001100101110001 |
3 | 11022211112101000222021011 |
4 | 101302030221221211301 |
5 | 130010410343044221 |
6 | 2333234452430521 |
7 | 154203350225632 |
oct | 21621451514561 |
9 | 4284471028234 |
10 | 1222130440561 |
11 | 431336855698 |
12 | 178a35018441 |
13 | 8b32847ab54 |
14 | 43219741889 |
15 | 21bcc9d31e1 |
hex | 11c8ca69971 |
1222130440561 has 2 divisors, whose sum is σ = 1222130440562. Its totient is φ = 1222130440560.
The previous prime is 1222130440523. The next prime is 1222130440571. The reversal of 1222130440561 is 1650440312221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1076945817600 + 145184622961 = 1037760^2 + 381031^2 .
It is a cyclic number.
It is not a de Polignac number, because 1222130440561 - 215 = 1222130407793 is a prime.
It is not a weakly prime, because it can be changed into another prime (1222130440571) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611065220280 + 611065220281.
It is an arithmetic number, because the mean of its divisors is an integer number (611065220281).
Almost surely, 21222130440561 is an apocalyptic number.
It is an amenable number.
1222130440561 is a deficient number, since it is larger than the sum of its proper divisors (1).
1222130440561 is an equidigital number, since it uses as much as digits as its factorization.
1222130440561 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 1222130440561 its reverse (1650440312221), we get a palindrome (2872570752782).
The spelling of 1222130440561 in words is "one trillion, two hundred twenty-two billion, one hundred thirty million, four hundred forty thousand, five hundred sixty-one".
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