Base | Representation |
---|---|
bin | 1011000111011000000010… |
… | …1100010000010110010011 |
3 | 1121021100102021022001102022 |
4 | 2301312000230100112103 |
5 | 3100213301301321232 |
6 | 41554223452442055 |
7 | 2400651136562033 |
oct | 261660054202623 |
9 | 47240367261368 |
10 | 12221341042067 |
11 | 3992050454853 |
12 | 14546b247932b |
13 | 6a86101915b1 |
14 | 30373210b8c3 |
15 | 162d89c0b812 |
hex | b1d80b10593 |
12221341042067 has 2 divisors, whose sum is σ = 12221341042068. Its totient is φ = 12221341042066.
The previous prime is 12221341042039. The next prime is 12221341042139. The reversal of 12221341042067 is 76024014312221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12221341042067 - 214 = 12221341025683 is a prime.
It is a super-2 number, since 2×122213410420672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12221341044067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6110670521033 + 6110670521034.
It is an arithmetic number, because the mean of its divisors is an integer number (6110670521034).
Almost surely, 212221341042067 is an apocalyptic number.
12221341042067 is a deficient number, since it is larger than the sum of its proper divisors (1).
12221341042067 is an equidigital number, since it uses as much as digits as its factorization.
12221341042067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 12221341042067 its reverse (76024014312221), we get a palindrome (88245355354288).
The spelling of 12221341042067 in words is "twelve trillion, two hundred twenty-one billion, three hundred forty-one million, forty-two thousand, sixty-seven".
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