Base | Representation |
---|---|
bin | 11011110010100010001111… |
… | …110000000000000100010011 |
3 | 121000202010012000111201122022 |
4 | 123302202033300000010103 |
5 | 112004423030240200201 |
6 | 1111535032101002055 |
7 | 34513050364164251 |
oct | 3362421760000423 |
9 | 530663160451568 |
10 | 122220001100051 |
11 | 35a41236396748 |
12 | 1185b07b0b332b |
13 | 53273b198174a |
14 | 22276a00d15d1 |
15 | e1e35198e41b |
hex | 6f288fc00113 |
122220001100051 has 2 divisors, whose sum is σ = 122220001100052. Its totient is φ = 122220001100050.
The previous prime is 122220001100027. The next prime is 122220001100209. The reversal of 122220001100051 is 150001100022221.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122220001100051 is a prime.
It is a super-2 number, since 2×1222200011000512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122220001100251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61110000550025 + 61110000550026.
It is an arithmetic number, because the mean of its divisors is an integer number (61110000550026).
Almost surely, 2122220001100051 is an apocalyptic number.
122220001100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
122220001100051 is an equidigital number, since it uses as much as digits as its factorization.
122220001100051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 122220001100051 its reverse (150001100022221), we get a palindrome (272221101122272).
The spelling of 122220001100051 in words is "one hundred twenty-two trillion, two hundred twenty billion, one million, one hundred thousand, fifty-one".
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