Base | Representation |
---|---|
bin | 10110110000111110… |
… | …10100100111000011 |
3 | 1011112202220011012102 |
4 | 23120133110213003 |
5 | 200012314233011 |
6 | 5340440221015 |
7 | 611605330262 |
oct | 133037244703 |
9 | 34482804172 |
10 | 12222024131 |
11 | 5202017699 |
12 | 245116a76b |
13 | 11ca160655 |
14 | 83d2d45d9 |
15 | 4b7eca73b |
hex | 2d87d49c3 |
12222024131 has 2 divisors, whose sum is σ = 12222024132. Its totient is φ = 12222024130.
The previous prime is 12222024053. The next prime is 12222024167. The reversal of 12222024131 is 13142022221.
It is a strong prime.
It is an emirp because it is prime and its reverse (13142022221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12222024131 is a prime.
It is a super-2 number, since 2×122220241312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (12222024181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111012065 + 6111012066.
It is an arithmetic number, because the mean of its divisors is an integer number (6111012066).
Almost surely, 212222024131 is an apocalyptic number.
12222024131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12222024131 is an equidigital number, since it uses as much as digits as its factorization.
12222024131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 12222024131 its reverse (13142022221), we get a palindrome (25364046352).
The spelling of 12222024131 in words is "twelve billion, two hundred twenty-two million, twenty-four thousand, one hundred thirty-one".
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