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12222111209953 is a prime number
BaseRepresentation
bin1011000111011010111010…
…0110001101100111100001
31121021102101221111122010211
42301312232212031213201
53100221340432204303
641554432124054121
72401006211106331
oct261665646154741
947242357448124
1012222111209953
11399240616a337
121454888394341
136a87038caa38
143037a650d0c1
15162dd263e66d
hexb1dae98d9e1

12222111209953 has 2 divisors, whose sum is σ = 12222111209954. Its totient is φ = 12222111209952.

The previous prime is 12222111209887. The next prime is 12222111210013. The reversal of 12222111209953 is 35990211122221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10885664231649 + 1336446978304 = 3299343^2 + 1156048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12222111209953 is a prime.

It is not a weakly prime, because it can be changed into another prime (12222111509953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111055604976 + 6111055604977.

It is an arithmetic number, because the mean of its divisors is an integer number (6111055604977).

Almost surely, 212222111209953 is an apocalyptic number.

It is an amenable number.

12222111209953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12222111209953 is an equidigital number, since it uses as much as digits as its factorization.

12222111209953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 40.

The spelling of 12222111209953 in words is "twelve trillion, two hundred twenty-two billion, one hundred eleven million, two hundred nine thousand, nine hundred fifty-three".