Base | Representation |
---|---|
bin | 10001110010010010101… |
… | …101000100011101001111 |
3 | 11022211210110010202002021 |
4 | 101302102231010131033 |
5 | 130011112343002320 |
6 | 2333252521311011 |
7 | 154206022405363 |
oct | 21622255043517 |
9 | 4284713122067 |
10 | 1222232000335 |
11 | 431389111a95 |
12 | 178a63035467 |
13 | 8b3435195a8 |
14 | 4322901b2a3 |
15 | 21bd6894daa |
hex | 11c92b4474f |
1222232000335 has 16 divisors (see below), whose sum is σ = 1470792495744. Its totient is φ = 975043521792.
The previous prime is 1222232000279. The next prime is 1222232000383. The reversal of 1222232000335 is 5330002322221.
It is a cyclic number.
It is not a de Polignac number, because 1222232000335 - 235 = 1187872261967 is a prime.
It is a super-2 number, since 2×12222320003352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16941099 + ... + 17013091.
It is an arithmetic number, because the mean of its divisors is an integer number (91924530984).
Almost surely, 21222232000335 is an apocalyptic number.
1222232000335 is a deficient number, since it is larger than the sum of its proper divisors (248560495409).
1222232000335 is an equidigital number, since it uses as much as digits as its factorization.
1222232000335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81474.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 1222232000335 its reverse (5330002322221), we get a palindrome (6552234322556).
The spelling of 1222232000335 in words is "one trillion, two hundred twenty-two billion, two hundred thirty-two million, three hundred thirty-five", and thus it is an aban number.
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