Base | Representation |
---|---|
bin | 1011000111011011101100… |
… | …0011011111110010110011 |
3 | 1121021102221111210002122202 |
4 | 2301312323003133302303 |
5 | 3100222302433310141 |
6 | 41554504551453415 |
7 | 2401014326442215 |
oct | 261667303376263 |
9 | 47242844702582 |
10 | 12222320213171 |
11 | 3992503141572 |
12 | 145492638726b |
13 | 6a8737cb7c93 |
14 | 3037c61965b5 |
15 | 162de5b7649b |
hex | b1dbb0dfcb3 |
12222320213171 has 2 divisors, whose sum is σ = 12222320213172. Its totient is φ = 12222320213170.
The previous prime is 12222320213167. The next prime is 12222320213239. The reversal of 12222320213171 is 17131202322221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12222320213171 - 22 = 12222320213167 is a prime.
It is a super-2 number, since 2×122223202131712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12222320213371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6111160106585 + 6111160106586.
It is an arithmetic number, because the mean of its divisors is an integer number (6111160106586).
Almost surely, 212222320213171 is an apocalyptic number.
12222320213171 is a deficient number, since it is larger than the sum of its proper divisors (1).
12222320213171 is an equidigital number, since it uses as much as digits as its factorization.
12222320213171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 12222320213171 its reverse (17131202322221), we get a palindrome (29353522535392).
The spelling of 12222320213171 in words is "twelve trillion, two hundred twenty-two billion, three hundred twenty million, two hundred thirteen thousand, one hundred seventy-one".
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