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122230400022433 is a prime number
BaseRepresentation
bin11011110010101011111011…
…100100101111011110100001
3121000210010000201220201101201
4123302223323210233132201
5112010110324401204213
61111543512014001201
734513566154442233
oct3362537344573641
9530703021821351
10122230400022433
1135a456922aaa7a
12118610a17a6201
13532837b1c3b61
142227da9218253
15e1e75e89b6dd
hex6f2afb92f7a1

122230400022433 has 2 divisors, whose sum is σ = 122230400022434. Its totient is φ = 122230400022432.

The previous prime is 122230400022391. The next prime is 122230400022449. The reversal of 122230400022433 is 334220004032221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 117310929254289 + 4919470768144 = 10831017^2 + 2217988^2 .

It is a cyclic number.

It is not a de Polignac number, because 122230400022433 - 241 = 120031376766881 is a prime.

It is not a weakly prime, because it can be changed into another prime (122230400020433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61115200011216 + 61115200011217.

It is an arithmetic number, because the mean of its divisors is an integer number (61115200011217).

Almost surely, 2122230400022433 is an apocalyptic number.

It is an amenable number.

122230400022433 is a deficient number, since it is larger than the sum of its proper divisors (1).

122230400022433 is an equidigital number, since it uses as much as digits as its factorization.

122230400022433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 122230400022433 its reverse (334220004032221), we get a palindrome (456450404054654).

The spelling of 122230400022433 in words is "one hundred twenty-two trillion, two hundred thirty billion, four hundred million, twenty-two thousand, four hundred thirty-three".