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122230999993 is a prime number
BaseRepresentation
bin111000111010110001…
…0010000101110111001
3102200111111012011010211
41301311202100232321
54000312113444433
6132052510311121
711554666233364
oct1616542205671
9380444164124
10122230999993
1147924238473
121b832ab84a1
13b6ac480bcb
145cb77730db
1532a5c978cd
hex1c75890bb9

122230999993 has 2 divisors, whose sum is σ = 122230999994. Its totient is φ = 122230999992.

The previous prime is 122230999981. The next prime is 122231000011. The reversal of 122230999993 is 399999032221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112324181904 + 9906818089 = 335148^2 + 99533^2 .

It is a cyclic number.

It is not a de Polignac number, because 122230999993 - 213 = 122230991801 is a prime.

It is not a weakly prime, because it can be changed into another prime (122230999193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61115499996 + 61115499997.

It is an arithmetic number, because the mean of its divisors is an integer number (61115499997).

Almost surely, 2122230999993 is an apocalyptic number.

It is an amenable number.

122230999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

122230999993 is an equidigital number, since it uses as much as digits as its factorization.

122230999993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4251528, while the sum is 58.

The spelling of 122230999993 in words is "one hundred twenty-two billion, two hundred thirty million, nine hundred ninety-nine thousand, nine hundred ninety-three".