Base | Representation |
---|---|
bin | 11011110010110110110110… |
… | …110111111111011010000011 |
3 | 121000211020022101100022202222 |
4 | 123302312312313333122003 |
5 | 112010303341334424103 |
6 | 1111553132122201255 |
7 | 34514462665506563 |
oct | 3362666667773203 |
9 | 530736271308688 |
10 | 122242132342403 |
11 | 35a4a662952687 |
12 | 1186341695322b |
13 | 53294caa65818 |
14 | 222879d476da3 |
15 | e1ebe9894638 |
hex | 6f2db6dff683 |
122242132342403 has 2 divisors, whose sum is σ = 122242132342404. Its totient is φ = 122242132342402.
The previous prime is 122242132342397. The next prime is 122242132342411. The reversal of 122242132342403 is 304243231242221.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 122242132342403 - 226 = 122242065233539 is a prime.
It is not a weakly prime, because it can be changed into another prime (122242132342433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61121066171201 + 61121066171202.
It is an arithmetic number, because the mean of its divisors is an integer number (61121066171202).
Almost surely, 2122242132342403 is an apocalyptic number.
122242132342403 is a deficient number, since it is larger than the sum of its proper divisors (1).
122242132342403 is an equidigital number, since it uses as much as digits as its factorization.
122242132342403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 122242132342403 its reverse (304243231242221), we get a palindrome (426485363584624).
The spelling of 122242132342403 in words is "one hundred twenty-two trillion, two hundred forty-two billion, one hundred thirty-two million, three hundred forty-two thousand, four hundred three".
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