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12225056497 is a prime number
BaseRepresentation
bin10110110001010101…
…11000111011110001
31011112222121012211021
423120222320323301
5200014103301442
65341025215441
7611643160063
oct133052707361
934488535737
1012225056497
1152037a8985
122452191581
1311ca982954
1483d883733
154b83c8e67
hex2d8ab8ef1

12225056497 has 2 divisors, whose sum is σ = 12225056498. Its totient is φ = 12225056496.

The previous prime is 12225056461. The next prime is 12225056509. The reversal of 12225056497 is 79465052221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11797435456 + 427621041 = 108616^2 + 20679^2 .

It is an emirp because it is prime and its reverse (79465052221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12225056497 - 27 = 12225056369 is a prime.

It is a super-2 number, since 2×122250564972 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12225056197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6112528248 + 6112528249.

It is an arithmetic number, because the mean of its divisors is an integer number (6112528249).

Almost surely, 212225056497 is an apocalyptic number.

It is an amenable number.

12225056497 is a deficient number, since it is larger than the sum of its proper divisors (1).

12225056497 is an equidigital number, since it uses as much as digits as its factorization.

12225056497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 43.

The spelling of 12225056497 in words is "twelve billion, two hundred twenty-five million, fifty-six thousand, four hundred ninety-seven".