12230131320133 has 4 divisors (see below), whose sum is σ = 12230301295168. Its totient is φ = 12229961345100.

The previous prime is 12230131320131. The next prime is 12230131320149. The reversal of 12230131320133 is 33102313103221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12230131320133 - 2¹ = 12230131320131 is a prime.

It is a super-2 number, since 2×12230131320133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12230131320098 and 12230131320107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12230131320131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84879543 + ... + 85023508.

It is an arithmetic number, because the mean of its divisors is an integer number (3057575323792).

Almost surely, 2^{12230131320133} is an apocalyptic number.

It is an amenable number.

12230131320133 is a deficient number, since it is larger than the sum of its proper divisors (169975035).

12230131320133 is an equidigital number, since it uses as much as digits as its factorization.

12230131320133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 169975034.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 12230131320133 its reverse (33102313103221), we get a palindrome (45332444423354).

The spelling of 12230131320133 in words is "twelve trillion, two hundred thirty billion, one hundred thirty-one million, three hundred twenty thousand, one hundred thirty-three".