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122302213181041 is a prime number
BaseRepresentation
bin11011110011101110110011…
…111110001100111001110001
3121001000222101112001011021211
4123303232303332030321301
5112012244413033243131
61112040505555120121
734522020566302465
oct3363566376147161
9531028345034254
10122302213181041
1135a73093a23a33
1211872ba38a3041
135332084187a0a
14222b65c9704a5
15e215642645b1
hex6f3bb3f8ce71

122302213181041 has 2 divisors, whose sum is σ = 122302213181042. Its totient is φ = 122302213181040.

The previous prime is 122302213181003. The next prime is 122302213181069. The reversal of 122302213181041 is 140181312203221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101152883835441 + 21149329345600 = 10057479^2 + 4598840^2 .

It is a cyclic number.

It is not a de Polignac number, because 122302213181041 - 215 = 122302213148273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 122302213180994 and 122302213181012.

It is not a weakly prime, because it can be changed into another prime (122302213181641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61151106590520 + 61151106590521.

It is an arithmetic number, because the mean of its divisors is an integer number (61151106590521).

Almost surely, 2122302213181041 is an apocalyptic number.

It is an amenable number.

122302213181041 is a deficient number, since it is larger than the sum of its proper divisors (1).

122302213181041 is an equidigital number, since it uses as much as digits as its factorization.

122302213181041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 31.

Adding to 122302213181041 its reverse (140181312203221), we get a palindrome (262483525384262).

The spelling of 122302213181041 in words is "one hundred twenty-two trillion, three hundred two billion, two hundred thirteen million, one hundred eighty-one thousand, forty-one".