Base | Representation |
---|---|
bin | 1011000111111001100010… |
… | …0111101110101001111001 |
3 | 1121022012121220012120002012 |
4 | 2301332120213232221321 |
5 | 3100340210101141012 |
6 | 42002312005415305 |
7 | 2401420016330465 |
oct | 261763047565171 |
9 | 47265556176065 |
10 | 12230332443257 |
11 | 3995944902625 |
12 | 14563a170a535 |
13 | 6a9413c20a26 |
14 | 303d463254a5 |
15 | 16321428a622 |
hex | b1f989eea79 |
12230332443257 has 2 divisors, whose sum is σ = 12230332443258. Its totient is φ = 12230332443256.
The previous prime is 12230332443221. The next prime is 12230332443319. The reversal of 12230332443257 is 75234423303221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11235743104576 + 994589338681 = 3351976^2 + 997291^2 .
It is a cyclic number.
It is not a de Polignac number, because 12230332443257 - 236 = 12161612966521 is a prime.
It is not a weakly prime, because it can be changed into another prime (12230332403257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115166221628 + 6115166221629.
It is an arithmetic number, because the mean of its divisors is an integer number (6115166221629).
Almost surely, 212230332443257 is an apocalyptic number.
It is an amenable number.
12230332443257 is a deficient number, since it is larger than the sum of its proper divisors (1).
12230332443257 is an equidigital number, since it uses as much as digits as its factorization.
12230332443257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 725760, while the sum is 41.
Adding to 12230332443257 its reverse (75234423303221), we get a palindrome (87464755746478).
The spelling of 12230332443257 in words is "twelve trillion, two hundred thirty billion, three hundred thirty-two million, four hundred forty-three thousand, two hundred fifty-seven".
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