12231013331113 has 4 divisors (see below), whose sum is σ = 12515455501648. Its totient is φ = 11946571160580.

The previous prime is 12231013331111. The next prime is 12231013331183. The reversal of 12231013331113 is 31113331013221.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12231013331113 - 2¹ = 12231013331111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12231013331111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142221085203 + ... + 142221085288.

It is an arithmetic number, because the mean of its divisors is an integer number (3128863875412).

Almost surely, 2^{12231013331113} is an apocalyptic number.

It is an amenable number.

12231013331113 is a deficient number, since it is larger than the sum of its proper divisors (284442170535).

12231013331113 is an equidigital number, since it uses as much as digits as its factorization.

12231013331113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 284442170534.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 12231013331113 its reverse (31113331013221), we get a palindrome (43344344344334).

The spelling of 12231013331113 in words is "twelve trillion, two hundred thirty-one billion, thirteen million, three hundred thirty-one thousand, one hundred thirteen".