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122311312030003 is a prime number
BaseRepresentation
bin11011110011110111010010…
…010011100011100100110011
3121001001211212122010120120211
4123303313102103203210303
5112012422031334430003
61112045012511044551
734522462222243105
oct3363672223434463
9531054778116524
10122311312030003
1135a76a32a9a918
1211874902b10757
135332ba4267905
14222bc83157575
15e218e7e6996d
hex6f3dd24e3933

122311312030003 has 2 divisors, whose sum is σ = 122311312030004. Its totient is φ = 122311312030002.

The previous prime is 122311312029989. The next prime is 122311312030031. The reversal of 122311312030003 is 300030213113221.

It is a weak prime.

It is an emirp because it is prime and its reverse (300030213113221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 122311312030003 - 25 = 122311312029971 is a prime.

It is a super-3 number, since 3×1223113120300033 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (122311312030403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61155656015001 + 61155656015002.

It is an arithmetic number, because the mean of its divisors is an integer number (61155656015002).

Almost surely, 2122311312030003 is an apocalyptic number.

122311312030003 is a deficient number, since it is larger than the sum of its proper divisors (1).

122311312030003 is an equidigital number, since it uses as much as digits as its factorization.

122311312030003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 122311312030003 its reverse (300030213113221), we get a palindrome (422341525143224).

The spelling of 122311312030003 in words is "one hundred twenty-two trillion, three hundred eleven billion, three hundred twelve million, thirty thousand, three".