Base | Representation |
---|---|
bin | 1011000111111100110001… |
… | …1111010100010110110001 |
3 | 1121022021212112122211021112 |
4 | 2301333030133110112301 |
5 | 3100344000334403432 |
6 | 42002534213203105 |
7 | 2401450414105103 |
oct | 261771437242661 |
9 | 47267775584245 |
10 | 12231202653617 |
11 | 3996251038542 |
12 | 14565a5030495 |
13 | 6a95222b70bc |
14 | 303dc9b29573 |
15 | 1632658807b2 |
hex | b1fcc7d45b1 |
12231202653617 has 2 divisors, whose sum is σ = 12231202653618. Its totient is φ = 12231202653616.
The previous prime is 12231202653613. The next prime is 12231202653707. The reversal of 12231202653617 is 71635620213221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11232210399601 + 998992254016 = 3351449^2 + 999496^2 .
It is a cyclic number.
It is not a de Polignac number, because 12231202653617 - 22 = 12231202653613 is a prime.
It is not a weakly prime, because it can be changed into another prime (12231202653613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115601326808 + 6115601326809.
It is an arithmetic number, because the mean of its divisors is an integer number (6115601326809).
Almost surely, 212231202653617 is an apocalyptic number.
It is an amenable number.
12231202653617 is a deficient number, since it is larger than the sum of its proper divisors (1).
12231202653617 is an equidigital number, since it uses as much as digits as its factorization.
12231202653617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 181440, while the sum is 41.
Adding to 12231202653617 its reverse (71635620213221), we get a palindrome (83866822866838).
The spelling of 12231202653617 in words is "twelve trillion, two hundred thirty-one billion, two hundred two million, six hundred fifty-three thousand, six hundred seventeen".
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