12231300141131 has 2 divisors, whose sum is σ = 12231300141132. Its totient is φ = 12231300141130.

The previous prime is 12231300141091. The next prime is 12231300141143. The reversal of 12231300141131 is 13114100313221.

12231300141131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12231300141131 is a prime.

It is a super-2 number, since 2×12231300141131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12231300141097 and 12231300141106.

It is not a weakly prime, because it can be changed into another prime (12231360141131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6115650070565 + 6115650070566.

It is an arithmetic number, because the mean of its divisors is an integer number (6115650070566).

Almost surely, 2^{12231300141131} is an apocalyptic number.

12231300141131 is a deficient number, since it is larger than the sum of its proper divisors (1).

12231300141131 is an equidigital number, since it uses as much as digits as its factorization.

12231300141131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 12231300141131 its reverse (13114100313221), we get a palindrome (25345400454352).

The spelling of 12231300141131 in words is "twelve trillion, two hundred thirty-one billion, three hundred million, one hundred forty-one thousand, one hundred thirty-one".