Base | Representation |
---|---|
bin | 100100011100111… |
… | …1000110001111101 |
3 | 10011020112122212121 |
4 | 1020321320301331 |
5 | 10001110244313 |
6 | 321212002541 |
7 | 42211320211 |
oct | 11071706175 |
9 | 3136478777 |
10 | 1223134333 |
11 | 578477a23 |
12 | 2a1760451 |
13 | 166534435 |
14 | b8632941 |
15 | 725aa28d |
hex | 48e78c7d |
1223134333 has 4 divisors (see below), whose sum is σ = 1232765440. Its totient is φ = 1213503228.
The previous prime is 1223134331. The next prime is 1223134361. The reversal of 1223134333 is 3334313221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3334313221 = 31 ⋅107558491.
It is a cyclic number.
It is not a de Polignac number, because 1223134333 - 21 = 1223134331 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1223134298 and 1223134307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1223134331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4815363 + ... + 4815616.
It is an arithmetic number, because the mean of its divisors is an integer number (308191360).
Almost surely, 21223134333 is an apocalyptic number.
It is an amenable number.
1223134333 is a deficient number, since it is larger than the sum of its proper divisors (9631107).
1223134333 is an equidigital number, since it uses as much as digits as its factorization.
1223134333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9631106.
The product of its digits is 3888, while the sum is 25.
The square root of 1223134333 is about 34973.3374586984. The cubic root of 1223134333 is about 1069.4440099225. Note that the first 3 decimals are identical.
Adding to 1223134333 its reverse (3334313221), we get a palindrome (4557447554).
It can be divided in two parts, 12231 and 34333, that added together give a palindrome (46564).
The spelling of 1223134333 in words is "one billion, two hundred twenty-three million, one hundred thirty-four thousand, three hundred thirty-three".
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