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122315533001113 is a prime number
BaseRepresentation
bin11011110011111011001101…
…111001010010000110011001
3121001002020202210122010102011
4123303323031321102012121
5112013004202422013423
61112050551413105521
734523001635016244
oct3363731571220631
9531066683563364
10122315533001113
1135a787a968a9a1
12118756a06282a1
1353333c78a6a5a
14222c16398c25b
15e21a937dcb0d
hex6f3ecde52199

122315533001113 has 2 divisors, whose sum is σ = 122315533001114. Its totient is φ = 122315533001112.

The previous prime is 122315533001029. The next prime is 122315533001117. The reversal of 122315533001113 is 311100335513221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 116512767515664 + 5802765485449 = 10794108^2 + 2408893^2 .

It is a cyclic number.

It is not a de Polignac number, because 122315533001113 - 213 = 122315532992921 is a prime.

It is a super-2 number, since 2×1223155330011132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122315533001117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61157766500556 + 61157766500557.

It is an arithmetic number, because the mean of its divisors is an integer number (61157766500557).

Almost surely, 2122315533001113 is an apocalyptic number.

It is an amenable number.

122315533001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

122315533001113 is an equidigital number, since it uses as much as digits as its factorization.

122315533001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 122315533001113 its reverse (311100335513221), we get a palindrome (433415868514334).

The spelling of 122315533001113 in words is "one hundred twenty-two trillion, three hundred fifteen billion, five hundred thirty-three million, one thousand, one hundred thirteen".