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1223231421241 is a prime number
BaseRepresentation
bin10001110011001110010…
…001100011101100111001
311022221101002201120211101
4101303032101203230321
5130020134220434431
62333540022331401
7154242546345064
oct21631621435471
94287332646741
101223231421241
1143185127a785
121790a1889b61
138b4725b2ccb
14432c1a578db
1521c444ae961
hex11cce463b39

1223231421241 has 2 divisors, whose sum is σ = 1223231421242. Its totient is φ = 1223231421240.

The previous prime is 1223231421229. The next prime is 1223231421301. The reversal of 1223231421241 is 1421241323221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 745191930025 + 478039491216 = 863245^2 + 691404^2 .

It is a cyclic number.

It is not a de Polignac number, because 1223231421241 - 221 = 1223229324089 is a prime.

It is a super-2 number, since 2×12232314212412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1223231422241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 611615710620 + 611615710621.

It is an arithmetic number, because the mean of its divisors is an integer number (611615710621).

Almost surely, 21223231421241 is an apocalyptic number.

It is an amenable number.

1223231421241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1223231421241 is an equidigital number, since it uses as much as digits as its factorization.

1223231421241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 28.

Adding to 1223231421241 its reverse (1421241323221), we get a palindrome (2644472744462).

The spelling of 1223231421241 in words is "one trillion, two hundred twenty-three billion, two hundred thirty-one million, four hundred twenty-one thousand, two hundred forty-one".