Base | Representation |
---|---|
bin | 11011110100000100001000… |
… | …111111100011011001000110 |
3 | 121001010011111112210101222011 |
4 | 123310010020333203121012 |
5 | 112013133313243411032 |
6 | 1112055214244324434 |
7 | 34523461240612243 |
oct | 3364041077433106 |
9 | 531104445711864 |
10 | 122325114435142 |
11 | 35a818760a9113 |
12 | 118775153a371a |
13 | 5334293952148 |
14 | 222c7d22b65ca |
15 | e21e54a6b247 |
hex | 6f4108fe3646 |
122325114435142 has 4 divisors (see below), whose sum is σ = 183487671652716. Its totient is φ = 61162557217570.
The previous prime is 122325114435113. The next prime is 122325114435163. The reversal of 122325114435142 is 241534411523221.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 122325114435095 and 122325114435104.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30581278608784 + ... + 30581278608787.
It is an arithmetic number, because the mean of its divisors is an integer number (45871917913179).
Almost surely, 2122325114435142 is an apocalyptic number.
122325114435142 is a deficient number, since it is larger than the sum of its proper divisors (61162557217574).
122325114435142 is an equidigital number, since it uses as much as digits as its factorization.
122325114435142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61162557217573.
The product of its digits is 230400, while the sum is 40.
Adding to 122325114435142 its reverse (241534411523221), we get a palindrome (363859525958363).
The spelling of 122325114435142 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, one hundred fourteen million, four hundred thirty-five thousand, one hundred forty-two".
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