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122325114435142 = 261162557217571
BaseRepresentation
bin11011110100000100001000…
…111111100011011001000110
3121001010011111112210101222011
4123310010020333203121012
5112013133313243411032
61112055214244324434
734523461240612243
oct3364041077433106
9531104445711864
10122325114435142
1135a818760a9113
12118775153a371a
135334293952148
14222c7d22b65ca
15e21e54a6b247
hex6f4108fe3646

122325114435142 has 4 divisors (see below), whose sum is σ = 183487671652716. Its totient is φ = 61162557217570.

The previous prime is 122325114435113. The next prime is 122325114435163. The reversal of 122325114435142 is 241534411523221.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 122325114435095 and 122325114435104.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30581278608784 + ... + 30581278608787.

It is an arithmetic number, because the mean of its divisors is an integer number (45871917913179).

Almost surely, 2122325114435142 is an apocalyptic number.

122325114435142 is a deficient number, since it is larger than the sum of its proper divisors (61162557217574).

122325114435142 is an equidigital number, since it uses as much as digits as its factorization.

122325114435142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61162557217573.

The product of its digits is 230400, while the sum is 40.

Adding to 122325114435142 its reverse (241534411523221), we get a palindrome (363859525958363).

The spelling of 122325114435142 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, one hundred fourteen million, four hundred thirty-five thousand, one hundred forty-two".

Divisors: 1 2 61162557217571 122325114435142