Base | Representation |
---|---|
bin | 11011110100000100001001… |
… | …000010001101000010111010 |
3 | 121001010011111121002201012012 |
4 | 123310010021002031002322 |
5 | 112013133313433130132 |
6 | 1112055214311245522 |
7 | 34523461246535216 |
oct | 3364041102150272 |
9 | 531104447081165 |
10 | 122325115130042 |
11 | 35a81876533210 |
12 | 118775156798a2 |
13 | 5334293b36526 |
14 | 222c7d2417946 |
15 | e21e54b570b2 |
hex | 6f410908d0ba |
122325115130042 has 8 divisors (see below), whose sum is σ = 200168370212832. Its totient is φ = 55602325059100.
The previous prime is 122325115130039. The next prime is 122325115130059. The reversal of 122325115130042 is 240031511523221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 122325115129990 and 122325115130008.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2780116252934 + ... + 2780116252977.
It is an arithmetic number, because the mean of its divisors is an integer number (25021046276604).
Almost surely, 2122325115130042 is an apocalyptic number.
122325115130042 is a deficient number, since it is larger than the sum of its proper divisors (77843255082790).
122325115130042 is a wasteful number, since it uses less digits than its factorization.
122325115130042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5560232505924.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 122325115130042 its reverse (240031511523221), we get a palindrome (362356626653263).
The spelling of 122325115130042 in words is "one hundred twenty-two trillion, three hundred twenty-five billion, one hundred fifteen million, one hundred thirty thousand, forty-two".
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