Base | Representation |
---|---|
bin | 11011110100001000101110… |
… | …010011100011001000011010 |
3 | 121001010122012111110101101212 |
4 | 123310020232103203020122 |
5 | 112013223403030314432 |
6 | 1112101350433543122 |
7 | 34524024213256214 |
oct | 3364105623431032 |
9 | 531118174411355 |
10 | 122330035401242 |
11 | 35a83970934849 |
12 | 11878469414aa2 |
13 | 53348992cb2c6 |
14 | 222cb3ba835b4 |
15 | e22141ab02b2 |
hex | 6f422e4e321a |
122330035401242 has 16 divisors (see below), whose sum is σ = 185491247685120. Its totient is φ = 60500995719312.
The previous prime is 122330035401151. The next prime is 122330035401293. The reversal of 122330035401242 is 242104530033221.
It is a super-2 number, since 2×1223300354012422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 122330035401199 and 122330035401208.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 343875017 + ... + 344230572.
It is an arithmetic number, because the mean of its divisors is an integer number (11593202980320).
Almost surely, 2122330035401242 is an apocalyptic number.
122330035401242 is a deficient number, since it is larger than the sum of its proper divisors (63161212283878).
122330035401242 is a wasteful number, since it uses less digits than its factorization.
122330035401242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 688106557.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 122330035401242 its reverse (242104530033221), we get a palindrome (364434565434463).
The spelling of 122330035401242 in words is "one hundred twenty-two trillion, three hundred thirty billion, thirty-five million, four hundred one thousand, two hundred forty-two".
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