Base | Representation |
---|---|
bin | 11011110100001000111010… |
… | …101000111000101110011011 |
3 | 121001010122201220211000100222 |
4 | 123310020322220320232123 |
5 | 112013224314013240212 |
6 | 1112101423144550255 |
7 | 34524032305124546 |
oct | 3364107250705633 |
9 | 531118656730328 |
10 | 122330242321307 |
11 | 35a83a67713969 |
12 | 1187850678238b |
13 | 5334900139307 |
14 | 222cb5b34785d |
15 | e22154d34c72 |
hex | 6f423aa38b9b |
122330242321307 has 2 divisors, whose sum is σ = 122330242321308. Its totient is φ = 122330242321306.
The previous prime is 122330242321267. The next prime is 122330242321403. The reversal of 122330242321307 is 703123242033221.
It is a weak prime.
It is an emirp because it is prime and its reverse (703123242033221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122330242321307 - 214 = 122330242304923 is a prime.
It is not a weakly prime, because it can be changed into another prime (122330242326307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61165121160653 + 61165121160654.
It is an arithmetic number, because the mean of its divisors is an integer number (61165121160654).
Almost surely, 2122330242321307 is an apocalyptic number.
122330242321307 is a deficient number, since it is larger than the sum of its proper divisors (1).
122330242321307 is an equidigital number, since it uses as much as digits as its factorization.
122330242321307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 35.
Adding to 122330242321307 its reverse (703123242033221), we get a palindrome (825453484354528).
The spelling of 122330242321307 in words is "one hundred twenty-two trillion, three hundred thirty billion, two hundred forty-two million, three hundred twenty-one thousand, three hundred seven".
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