Base | Representation |
---|---|
bin | 1011001000000011110111… |
… | …0101101011010001010101 |
3 | 1121022110210002000111122111 |
4 | 2302000331311223101111 |
5 | 3100411344202340203 |
6 | 42003451025031021 |
7 | 2401545505140322 |
oct | 262007565532125 |
9 | 47273702014574 |
10 | 12233104340053 |
11 | 3997037535723 |
12 | 1456a35a85471 |
13 | 6a976628b44c |
14 | 30412a511b49 |
15 | 1633277c326d |
hex | b203dd6b455 |
12233104340053 has 4 divisors (see below), whose sum is σ = 12244317085728. Its totient is φ = 12221891594380.
The previous prime is 12233104339933. The next prime is 12233104340087. The reversal of 12233104340053 is 35004340133221.
It is a happy number.
12233104340053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12233104340053 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12233104339997 and 12233104340024.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12233104340153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5606371201 + ... + 5606373382.
It is an arithmetic number, because the mean of its divisors is an integer number (3061079271432).
Almost surely, 212233104340053 is an apocalyptic number.
It is an amenable number.
12233104340053 is a deficient number, since it is larger than the sum of its proper divisors (11212745675).
12233104340053 is a wasteful number, since it uses less digits than its factorization.
12233104340053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11212745674.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 12233104340053 its reverse (35004340133221), we get a palindrome (47237444473274).
The spelling of 12233104340053 in words is "twelve trillion, two hundred thirty-three billion, one hundred four million, three hundred forty thousand, fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •