Base | Representation |
---|---|
bin | 1011001000000110001111… |
… | …1110010011001001100011 |
3 | 1121022112102122220102222120 |
4 | 2302001203332103021203 |
5 | 3100414201444303010 |
6 | 42004034322035323 |
7 | 2401600404251103 |
oct | 262014376231143 |
9 | 47275378812876 |
10 | 12233744134755 |
11 | 39973356a3980 |
12 | 1456b941a8b43 |
13 | 6a98389ab2b0 |
14 | 30418b497203 |
15 | 163363a51e70 |
hex | b2063f93263 |
12233744134755 has 64 divisors (see below), whose sum is σ = 22999221084672. Its totient is φ = 5474479242240.
The previous prime is 12233744134741. The next prime is 12233744134831. The reversal of 12233744134755 is 55743144733221.
It is not a de Polignac number, because 12233744134755 - 24 = 12233744134739 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12233744134698 and 12233744134707.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15142519 + ... + 15929951.
It is an arithmetic number, because the mean of its divisors is an integer number (359362829448).
Almost surely, 212233744134755 is an apocalyptic number.
12233744134755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12233744134755 is a deficient number, since it is larger than the sum of its proper divisors (10765476949917).
12233744134755 is a wasteful number, since it uses less digits than its factorization.
12233744134755 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 794708.
The product of its digits is 8467200, while the sum is 51.
Adding to 12233744134755 its reverse (55743144733221), we get a palindrome (67976888867976).
The spelling of 12233744134755 in words is "twelve trillion, two hundred thirty-three billion, seven hundred forty-four million, one hundred thirty-four thousand, seven hundred fifty-five".
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