Base | Representation |
---|---|
bin | 10110110010011010… |
… | …11110010011101001 |
3 | 1011120121122211000011 |
4 | 23121031132103221 |
5 | 200023413404343 |
6 | 5341551411521 |
7 | 612113216356 |
oct | 133115362351 |
9 | 34517584004 |
10 | 12234122473 |
11 | 5208930321 |
12 | 2455223ba1 |
13 | 11cc808331 |
14 | 840b6362d |
15 | 4b90ba29d |
hex | 2d935e4e9 |
12234122473 has 2 divisors, whose sum is σ = 12234122474. Its totient is φ = 12234122472.
The previous prime is 12234122443. The next prime is 12234122489. The reversal of 12234122473 is 37422143221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6373148224 + 5860974249 = 79832^2 + 76557^2 .
It is an emirp because it is prime and its reverse (37422143221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12234122473 - 213 = 12234114281 is a prime.
It is not a weakly prime, because it can be changed into another prime (12234122423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6117061236 + 6117061237.
It is an arithmetic number, because the mean of its divisors is an integer number (6117061237).
Almost surely, 212234122473 is an apocalyptic number.
It is an amenable number.
12234122473 is a deficient number, since it is larger than the sum of its proper divisors (1).
12234122473 is an equidigital number, since it uses as much as digits as its factorization.
12234122473 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16128, while the sum is 31.
Adding to 12234122473 its reverse (37422143221), we get a palindrome (49656265694).
The spelling of 12234122473 in words is "twelve billion, two hundred thirty-four million, one hundred twenty-two thousand, four hundred seventy-three".
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