Base | Representation |
---|---|
bin | 11011110100010100110100… |
… | …010011101100010101111001 |
3 | 121001011212201111011100202211 |
4 | 123310110310103230111321 |
5 | 112013432001334113103 |
6 | 1112111335152255121 |
7 | 34524664053131635 |
oct | 3364246423542571 |
9 | 531155644140684 |
10 | 122343021004153 |
11 | 35a89424976484 |
12 | 1187aa922414a1 |
13 | 5335b886cbc01 |
14 | 222d610541dc5 |
15 | e22651b1b36d |
hex | 6f45344ec579 |
122343021004153 has 2 divisors, whose sum is σ = 122343021004154. Its totient is φ = 122343021004152.
The previous prime is 122343021004133. The next prime is 122343021004159. The reversal of 122343021004153 is 351400120343221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76007935372009 + 46335085632144 = 8718253^2 + 6806988^2 .
It is a cyclic number.
It is not a de Polignac number, because 122343021004153 - 217 = 122343020873081 is a prime.
It is not a weakly prime, because it can be changed into another prime (122343021004159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61171510502076 + 61171510502077.
It is an arithmetic number, because the mean of its divisors is an integer number (61171510502077).
Almost surely, 2122343021004153 is an apocalyptic number.
It is an amenable number.
122343021004153 is a deficient number, since it is larger than the sum of its proper divisors (1).
122343021004153 is an equidigital number, since it uses as much as digits as its factorization.
122343021004153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 122343021004153 its reverse (351400120343221), we get a palindrome (473743141347374).
The spelling of 122343021004153 in words is "one hundred twenty-two trillion, three hundred forty-three billion, twenty-one million, four thousand, one hundred fifty-three".
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