Base | Representation |
---|---|
bin | 111000111110000111… |
… | …1000101100101100001 |
3 | 102200210022201101022202 |
4 | 1301330033011211201 |
5 | 4001024403222423 |
6 | 132112003542545 |
7 | 11560532601344 |
oct | 1617417054541 |
9 | 380708641282 |
10 | 122343414113 |
11 | 479817388a8 |
12 | 1b86468aa55 |
13 | b6c985003b |
14 | 5cc867645b |
15 | 32b0aa0728 |
hex | 1c7c3c5961 |
122343414113 has 2 divisors, whose sum is σ = 122343414114. Its totient is φ = 122343414112.
The previous prime is 122343414107. The next prime is 122343414161. The reversal of 122343414113 is 311414343221.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 89630180689 + 32713233424 = 299383^2 + 180868^2 .
It is a cyclic number.
It is not a de Polignac number, because 122343414113 - 216 = 122343348577 is a prime.
It is not a weakly prime, because it can be changed into another prime (122343414013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61171707056 + 61171707057.
It is an arithmetic number, because the mean of its divisors is an integer number (61171707057).
Almost surely, 2122343414113 is an apocalyptic number.
It is an amenable number.
122343414113 is a deficient number, since it is larger than the sum of its proper divisors (1).
122343414113 is an equidigital number, since it uses as much as digits as its factorization.
122343414113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6912, while the sum is 29.
Adding to 122343414113 its reverse (311414343221), we get a palindrome (433757757334).
The spelling of 122343414113 in words is "one hundred twenty-two billion, three hundred forty-three million, four hundred fourteen thousand, one hundred thirteen".
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