Base | Representation |
---|---|
bin | 10110110010110100… |
… | …01001000000111011 |
3 | 1011120211220112002111 |
4 | 23121122021000323 |
5 | 200030241140011 |
6 | 5342150513151 |
7 | 612153356524 |
oct | 133132110073 |
9 | 34524815074 |
10 | 12237443131 |
11 | 520a799171 |
12 | 24563657b7 |
13 | 12003cb914 |
14 | 84138984b |
15 | 4b9524121 |
hex | 2d968903b |
12237443131 has 2 divisors, whose sum is σ = 12237443132. Its totient is φ = 12237443130.
The previous prime is 12237443093. The next prime is 12237443177. The reversal of 12237443131 is 13134473221.
It is a weak prime.
It is an emirp because it is prime and its reverse (13134473221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12237443131 - 213 = 12237434939 is a prime.
It is a super-2 number, since 2×122374431312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12237443093 and 12237443102.
It is not a weakly prime, because it can be changed into another prime (12237443431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6118721565 + 6118721566.
It is an arithmetic number, because the mean of its divisors is an integer number (6118721566).
Almost surely, 212237443131 is an apocalyptic number.
12237443131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12237443131 is an equidigital number, since it uses as much as digits as its factorization.
12237443131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12096, while the sum is 31.
The spelling of 12237443131 in words is "twelve billion, two hundred thirty-seven million, four hundred forty-three thousand, one hundred thirty-one".
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