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122401120431347 is a prime number
BaseRepresentation
bin11011110101001010111011…
…010011011010110011110011
3121001101102200112111001202122
4123311022323103122303303
5112020404443312300342
61112154144244504455
734532121604123022
oct3365127323326363
9531342615431678
10122401120431347
113600102954700a
121188a1a76ab12b
13533b4b74848b4
14223236281c8b9
15e23e0259b4d2
hex6f52bb4dacf3

122401120431347 has 2 divisors, whose sum is σ = 122401120431348. Its totient is φ = 122401120431346.

The previous prime is 122401120431211. The next prime is 122401120431449. The reversal of 122401120431347 is 743134021104221.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122401120431347 is a prime.

It is a super-2 number, since 2×1224011204313472 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122401120401347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61200560215673 + 61200560215674.

It is an arithmetic number, because the mean of its divisors is an integer number (61200560215674).

Almost surely, 2122401120431347 is an apocalyptic number.

122401120431347 is a deficient number, since it is larger than the sum of its proper divisors (1).

122401120431347 is an equidigital number, since it uses as much as digits as its factorization.

122401120431347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32256, while the sum is 35.

Adding to 122401120431347 its reverse (743134021104221), we get a palindrome (865535141535568).

The spelling of 122401120431347 in words is "one hundred twenty-two trillion, four hundred one billion, one hundred twenty million, four hundred thirty-one thousand, three hundred forty-seven".