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122402021435257 is a prime number
BaseRepresentation
bin11011110101001011110001…
…000000011110011101111001
3121001101112000022212210202211
4123311023301000132131321
5112020413314441412012
61112154413512255121
734532153124412414
oct3365136100363571
9531345008783684
10122402021435257
11360014510a4643
121188a3b93a14a1
13533b5cc0401c5
14223240a35ab7b
15e23e567256a7
hex6f52f101e779

122402021435257 has 2 divisors, whose sum is σ = 122402021435258. Its totient is φ = 122402021435256.

The previous prime is 122402021435251. The next prime is 122402021435279. The reversal of 122402021435257 is 752534120204221.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120675585739536 + 1726435695721 = 10985244^2 + 1313939^2 .

It is a cyclic number.

It is not a de Polignac number, because 122402021435257 - 231 = 122399873951609 is a prime.

It is a super-2 number, since 2×1224020214352572 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (122402021435251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61201010717628 + 61201010717629.

It is an arithmetic number, because the mean of its divisors is an integer number (61201010717629).

Almost surely, 2122402021435257 is an apocalyptic number.

It is an amenable number.

122402021435257 is a deficient number, since it is larger than the sum of its proper divisors (1).

122402021435257 is an equidigital number, since it uses as much as digits as its factorization.

122402021435257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 268800, while the sum is 40.

Adding to 122402021435257 its reverse (752534120204221), we get a palindrome (874936141639478).

The spelling of 122402021435257 in words is "one hundred twenty-two trillion, four hundred two billion, twenty-one million, four hundred thirty-five thousand, two hundred fifty-seven".