Base | Representation |
---|---|
bin | 11011110101010100011010… |
… | …010010101100100011110111 |
3 | 121001102101222020200120020022 |
4 | 123311110122102230203313 |
5 | 112021041322311341043 |
6 | 1112202550550155355 |
7 | 34532632141125425 |
oct | 3365243222544367 |
9 | 531371866616208 |
10 | 122411304012023 |
11 | 36005384949994 |
12 | 1189016a052b5b |
13 | 533c44b1ca990 |
14 | 2232a4b0cc115 |
15 | e242eb61d868 |
hex | 6f551a4ac8f7 |
122411304012023 has 4 divisors (see below), whose sum is σ = 131827558166808. Its totient is φ = 112995049857240.
The previous prime is 122411304011957. The next prime is 122411304012043. The reversal of 122411304012023 is 320210403114221.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 122411304012023 - 214 = 122411303995639 is a prime.
It is a super-2 number, since 2×1224113040120232 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122411304011983 and 122411304012001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122411304012043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4708127077373 + ... + 4708127077398.
It is an arithmetic number, because the mean of its divisors is an integer number (32956889541702).
Almost surely, 2122411304012023 is an apocalyptic number.
122411304012023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
122411304012023 is a deficient number, since it is larger than the sum of its proper divisors (9416254154785).
122411304012023 is an equidigital number, since it uses as much as digits as its factorization.
122411304012023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9416254154784.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 122411304012023 its reverse (320210403114221), we get a palindrome (442621707126244).
The spelling of 122411304012023 in words is "one hundred twenty-two trillion, four hundred eleven billion, three hundred four million, twelve thousand, twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •