Base | Representation |
---|---|
bin | 10001110100000010110… |
… | …110111100010010001001 |
3 | 11100000122120202202122012 |
4 | 101310002312330102021 |
5 | 130023441042331424 |
6 | 2334203335305305 |
7 | 154303451142152 |
oct | 21640266742211 |
9 | 4300576682565 |
10 | 1224113636489 |
11 | 432164265097 |
12 | 1792a921b235 |
13 | 8b5832c0673 |
14 | 43366ca4929 |
15 | 21c96b76b0e |
hex | 11d02dbc489 |
1224113636489 has 2 divisors, whose sum is σ = 1224113636490. Its totient is φ = 1224113636488.
The previous prime is 1224113636419. The next prime is 1224113636507. The reversal of 1224113636489 is 9846363114221.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1091049188089 + 133064448400 = 1044533^2 + 364780^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1224113636489 is a prime.
It is not a weakly prime, because it can be changed into another prime (1224113636419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612056818244 + 612056818245.
It is an arithmetic number, because the mean of its divisors is an integer number (612056818245).
Almost surely, 21224113636489 is an apocalyptic number.
It is an amenable number.
1224113636489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1224113636489 is an equidigital number, since it uses as much as digits as its factorization.
1224113636489 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1492992, while the sum is 50.
The spelling of 1224113636489 in words is "one trillion, two hundred twenty-four billion, one hundred thirteen million, six hundred thirty-six thousand, four hundred eighty-nine".
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