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1224122113 is a prime number
BaseRepresentation
bin100100011110110…
…1001111100000001
310011022101211212001
41020331221330001
510001333401423
6321245104001
742222603064
oct11075517401
93138354761
101224122113
11578a92075
122a1b58001
131667bbc16
14b880c8db
1572702cad
hex48f69f01

1224122113 has 2 divisors, whose sum is σ = 1224122114. Its totient is φ = 1224122112.

The previous prime is 1224122089. The next prime is 1224122129. The reversal of 1224122113 is 3112214221.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 702091009 + 522031104 = 26497^2 + 22848^2 .

It is an emirp because it is prime and its reverse (3112214221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1224122113 - 221 = 1222024961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1224122413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612061056 + 612061057.

It is an arithmetic number, because the mean of its divisors is an integer number (612061057).

Almost surely, 21224122113 is an apocalyptic number.

It is an amenable number.

1224122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1224122113 is an equidigital number, since it uses as much as digits as its factorization.

1224122113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 192, while the sum is 19.

The square root of 1224122113 is about 34987.4565094406. The cubic root of 1224122113 is about 1069.7318200001.

Adding to 1224122113 its reverse (3112214221), we get a palindrome (4336336334).

The spelling of 1224122113 in words is "one billion, two hundred twenty-four million, one hundred twenty-two thousand, one hundred thirteen".