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122413104983 = 139416392691
BaseRepresentation
bin111001000000001100…
…0111011111101010111
3102200222011212001020002
41302000120323331113
54001200223324413
6132122533401515
711562340136621
oct1620030737527
9380864761202
10122413104983
1147a08008664
121b883a9929b
13b70b110c40
145cd3a17c11
1532b6c69958
hex1c8063bf57

122413104983 has 4 divisors (see below), whose sum is σ = 131829497688. Its totient is φ = 112996712280.

The previous prime is 122413104937. The next prime is 122413104991. The reversal of 122413104983 is 389401314221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-122413104983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (122413104683) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4708196333 + ... + 4708196358.

It is an arithmetic number, because the mean of its divisors is an integer number (32957374422).

Almost surely, 2122413104983 is an apocalyptic number.

122413104983 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

122413104983 is a deficient number, since it is larger than the sum of its proper divisors (9416392705).

122413104983 is an equidigital number, since it uses as much as digits as its factorization.

122413104983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9416392704.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 122413104983 in words is "one hundred twenty-two billion, four hundred thirteen million, one hundred four thousand, nine hundred eighty-three".

Divisors: 1 13 9416392691 122413104983