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122413141234283 is a prime number
BaseRepresentation
bin11011110101010110000111…
…110011001001001001101011
3121001102120201021202010101012
4123311112013303021021223
5112021104103123444113
61112203453140214135
734533025520221514
oct3365260763111153
9531376637663335
10122413141234283
1136006137a17199
12118905a139a34b
13533c681a21143
142232b830d3a0b
15e243a7a7aaa8
hex6f5587cc926b

122413141234283 has 2 divisors, whose sum is σ = 122413141234284. Its totient is φ = 122413141234282.

The previous prime is 122413141234207. The next prime is 122413141234331. The reversal of 122413141234283 is 382432141314221.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 122413141234283 - 210 = 122413141233259 is a prime.

It is a Sophie Germain prime.

It is a self number, because there is not a number n which added to its sum of digits gives 122413141234283.

It is not a weakly prime, because it can be changed into another prime (122413141239283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61206570617141 + 61206570617142.

It is an arithmetic number, because the mean of its divisors is an integer number (61206570617142).

Almost surely, 2122413141234283 is an apocalyptic number.

122413141234283 is a deficient number, since it is larger than the sum of its proper divisors (1).

122413141234283 is an equidigital number, since it uses as much as digits as its factorization.

122413141234283 is an evil number, because the sum of its binary digits is even.

The product of its digits is 221184, while the sum is 41.

The spelling of 122413141234283 in words is "one hundred twenty-two trillion, four hundred thirteen billion, one hundred forty-one million, two hundred thirty-four thousand, two hundred eighty-three".