Base | Representation |
---|---|
bin | 11011110101010110000111… |
… | …110011001001001001101011 |
3 | 121001102120201021202010101012 |
4 | 123311112013303021021223 |
5 | 112021104103123444113 |
6 | 1112203453140214135 |
7 | 34533025520221514 |
oct | 3365260763111153 |
9 | 531376637663335 |
10 | 122413141234283 |
11 | 36006137a17199 |
12 | 118905a139a34b |
13 | 533c681a21143 |
14 | 2232b830d3a0b |
15 | e243a7a7aaa8 |
hex | 6f5587cc926b |
122413141234283 has 2 divisors, whose sum is σ = 122413141234284. Its totient is φ = 122413141234282.
The previous prime is 122413141234207. The next prime is 122413141234331. The reversal of 122413141234283 is 382432141314221.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 122413141234283 - 210 = 122413141233259 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 122413141234283.
It is not a weakly prime, because it can be changed into another prime (122413141239283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61206570617141 + 61206570617142.
It is an arithmetic number, because the mean of its divisors is an integer number (61206570617142).
Almost surely, 2122413141234283 is an apocalyptic number.
122413141234283 is a deficient number, since it is larger than the sum of its proper divisors (1).
122413141234283 is an equidigital number, since it uses as much as digits as its factorization.
122413141234283 is an evil number, because the sum of its binary digits is even.
The product of its digits is 221184, while the sum is 41.
The spelling of 122413141234283 in words is "one hundred twenty-two trillion, four hundred thirteen billion, one hundred forty-one million, two hundred thirty-four thousand, two hundred eighty-three".
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