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12241321000043 is a prime number
BaseRepresentation
bin1011001000100010011110…
…0101101111110001101011
31121100020222201010002011212
42302020213211233301223
53101030211134000133
642011330224343335
72402256226453262
oct262104745576153
947306881102155
1012241321000043
11399a573634a13
121458549774b4b
136aa47566c935
143046a98975d9
15163658d19148
hexb222796fc6b

12241321000043 has 2 divisors, whose sum is σ = 12241321000044. Its totient is φ = 12241321000042.

The previous prime is 12241320999953. The next prime is 12241321000063. The reversal of 12241321000043 is 34000012314221.

It is a strong prime.

It is an emirp because it is prime and its reverse (34000012314221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12241321000043 - 214 = 12241320983659 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12241320999982 and 12241321000018.

It is not a weakly prime, because it can be changed into another prime (12241321000063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6120660500021 + 6120660500022.

It is an arithmetic number, because the mean of its divisors is an integer number (6120660500022).

Almost surely, 212241321000043 is an apocalyptic number.

12241321000043 is a deficient number, since it is larger than the sum of its proper divisors (1).

12241321000043 is an equidigital number, since it uses as much as digits as its factorization.

12241321000043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12241321000043 its reverse (34000012314221), we get a palindrome (46241333314264).

The spelling of 12241321000043 in words is "twelve trillion, two hundred forty-one billion, three hundred twenty-one million, forty-three", and thus it is an aban number.