Base | Representation |
---|---|
bin | 1011001000100010011110… |
… | …0101101111110001101011 |
3 | 1121100020222201010002011212 |
4 | 2302020213211233301223 |
5 | 3101030211134000133 |
6 | 42011330224343335 |
7 | 2402256226453262 |
oct | 262104745576153 |
9 | 47306881102155 |
10 | 12241321000043 |
11 | 399a573634a13 |
12 | 1458549774b4b |
13 | 6aa47566c935 |
14 | 3046a98975d9 |
15 | 163658d19148 |
hex | b222796fc6b |
12241321000043 has 2 divisors, whose sum is σ = 12241321000044. Its totient is φ = 12241321000042.
The previous prime is 12241320999953. The next prime is 12241321000063. The reversal of 12241321000043 is 34000012314221.
It is a strong prime.
It is an emirp because it is prime and its reverse (34000012314221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12241321000043 - 214 = 12241320983659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12241320999982 and 12241321000018.
It is not a weakly prime, because it can be changed into another prime (12241321000063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6120660500021 + 6120660500022.
It is an arithmetic number, because the mean of its divisors is an integer number (6120660500022).
Almost surely, 212241321000043 is an apocalyptic number.
12241321000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
12241321000043 is an equidigital number, since it uses as much as digits as its factorization.
12241321000043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 12241321000043 its reverse (34000012314221), we get a palindrome (46241333314264).
The spelling of 12241321000043 in words is "twelve trillion, two hundred forty-one billion, three hundred twenty-one million, forty-three", and thus it is an aban number.
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