Base | Representation |
---|---|
bin | 11011110101010111111001… |
… | …000011010101100111011111 |
3 | 121001102202121201001201110202 |
4 | 123311113321003111213133 |
5 | 112021122001033230210 |
6 | 1112204405453254115 |
7 | 34533123561444452 |
oct | 3365277103254737 |
9 | 531382551051422 |
10 | 122415041305055 |
11 | 36006a22510514 |
12 | 11890a3179433b |
13 | 533c8c557ac85 |
14 | 2232cc35b9499 |
15 | e2446979e9a5 |
hex | 6f55f90d59df |
122415041305055 has 4 divisors (see below), whose sum is σ = 146898049566072. Its totient is φ = 97932033044040.
The previous prime is 122415041305019. The next prime is 122415041305061. The reversal of 122415041305055 is 550503140514221.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 122415041305055 - 230 = 122413967563231 is a prime.
It is a super-3 number, since 3×1224150413050553 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12241504130501 + ... + 12241504130510.
It is an arithmetic number, because the mean of its divisors is an integer number (36724512391518).
Almost surely, 2122415041305055 is an apocalyptic number.
122415041305055 is a deficient number, since it is larger than the sum of its proper divisors (24483008261017).
122415041305055 is an equidigital number, since it uses as much as digits as its factorization.
122415041305055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24483008261016.
The product of its (nonzero) digits is 120000, while the sum is 38.
Adding to 122415041305055 its reverse (550503140514221), we get a palindrome (672918181819276).
The spelling of 122415041305055 in words is "one hundred twenty-two trillion, four hundred fifteen billion, forty-one million, three hundred five thousand, fifty-five".
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