Base | Representation |
---|---|
bin | 11011110101101001000101… |
… | …011110110001010100101011 |
3 | 121001111112021100211001021021 |
4 | 123311221011132301110223 |
5 | 112021422303334342102 |
6 | 1112221101444553311 |
7 | 34534346231113402 |
oct | 3365510536612453 |
9 | 531445240731237 |
10 | 122433503434027 |
11 | 36013836943245 |
12 | 118945246b2837 |
13 | 5341578463b46 |
14 | 2233b55540639 |
15 | e24b9a4e0137 |
hex | 6f5a457b152b |
122433503434027 has 2 divisors, whose sum is σ = 122433503434028. Its totient is φ = 122433503434026.
The previous prime is 122433503434003. The next prime is 122433503434049. The reversal of 122433503434027 is 720434305334221.
It is a strong prime.
It is an emirp because it is prime and its reverse (720434305334221) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-122433503434027 is a prime.
It is not a weakly prime, because it can be changed into another prime (122433503434727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61216751717013 + 61216751717014.
It is an arithmetic number, because the mean of its divisors is an integer number (61216751717014).
Almost surely, 2122433503434027 is an apocalyptic number.
122433503434027 is a deficient number, since it is larger than the sum of its proper divisors (1).
122433503434027 is an equidigital number, since it uses as much as digits as its factorization.
122433503434027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 43.
Adding to 122433503434027 its reverse (720434305334221), we get a palindrome (842867808768248).
The spelling of 122433503434027 in words is "one hundred twenty-two trillion, four hundred thirty-three billion, five hundred three million, four hundred thirty-four thousand, twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •