Base | Representation |
---|---|
bin | 10110110011100001… |
… | …11101010001010111 |
3 | 1011121021011101202212 |
4 | 23121300331101113 |
5 | 200033304034333 |
6 | 5342523024035 |
7 | 612255250463 |
oct | 133160752127 |
9 | 34537141685 |
10 | 12243424343 |
11 | 5213103a17 |
12 | 245836b01b |
13 | 12017141b7 |
14 | 8420a54a3 |
15 | 4b9d06448 |
hex | 2d9c3d457 |
12243424343 has 4 divisors (see below), whose sum is σ = 12260128248. Its totient is φ = 12226720440.
The previous prime is 12243424337. The next prime is 12243424351. The reversal of 12243424343 is 34342434221.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12243424343 - 216 = 12243358807 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12243424313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8350853 + ... + 8352318.
It is an arithmetic number, because the mean of its divisors is an integer number (3065032062).
Almost surely, 212243424343 is an apocalyptic number.
12243424343 is a deficient number, since it is larger than the sum of its proper divisors (16703905).
12243424343 is an equidigital number, since it uses as much as digits as its factorization.
12243424343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16703904.
The product of its digits is 55296, while the sum is 32.
Adding to 12243424343 its reverse (34342434221), we get a palindrome (46585858564).
The spelling of 12243424343 in words is "twelve billion, two hundred forty-three million, four hundred twenty-four thousand, three hundred forty-three".
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