Base | Representation |
---|---|
bin | 111001000001000001… |
… | …1010111010001100101 |
3 | 102201001010100110122221 |
4 | 1302002003113101211 |
5 | 4001224344113013 |
6 | 132125411352341 |
7 | 11563126235350 |
oct | 1620203272145 |
9 | 381033313587 |
10 | 122441004133 |
11 | 47a21833708 |
12 | 1b8912b26b1 |
13 | b713b2b906 |
14 | 5cd75db297 |
15 | 32b942b08d |
hex | 1c820d7465 |
122441004133 has 4 divisors (see below), whose sum is σ = 139932576160. Its totient is φ = 104949432108.
The previous prime is 122441004113. The next prime is 122441004149. The reversal of 122441004133 is 331400144221.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 122441004133 - 29 = 122441003621 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 122441004098 and 122441004107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (122441004113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8745786003 + ... + 8745786016.
It is an arithmetic number, because the mean of its divisors is an integer number (34983144040).
Almost surely, 2122441004133 is an apocalyptic number.
It is an amenable number.
122441004133 is a deficient number, since it is larger than the sum of its proper divisors (17491572027).
122441004133 is an equidigital number, since it uses as much as digits as its factorization.
122441004133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17491572026.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 122441004133 its reverse (331400144221), we get a palindrome (453841148354).
The spelling of 122441004133 in words is "one hundred twenty-two billion, four hundred forty-one million, four thousand, one hundred thirty-three".
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