Base | Representation |
---|---|
bin | 111001000001000001… |
… | …1110110001111111011 |
3 | 102201001010120220200211 |
4 | 1302002003312033323 |
5 | 4001224412143003 |
6 | 132125414211551 |
7 | 11563130304262 |
oct | 1620203661773 |
9 | 381033526624 |
10 | 122441131003 |
11 | 47a2190aa64 |
12 | 1b891353bb7 |
13 | b713b74599 |
14 | 5cd76315d9 |
15 | 32b945396d |
hex | 1c820f63fb |
122441131003 has 2 divisors, whose sum is σ = 122441131004. Its totient is φ = 122441131002.
The previous prime is 122441130983. The next prime is 122441131027. The reversal of 122441131003 is 300131144221.
It is a weak prime.
It is an emirp because it is prime and its reverse (300131144221) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 122441131003 - 217 = 122440999931 is a prime.
It is a super-2 number, since 2×1224411310032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (122441131063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 61220565501 + 61220565502.
It is an arithmetic number, because the mean of its divisors is an integer number (61220565502).
Almost surely, 2122441131003 is an apocalyptic number.
122441131003 is a deficient number, since it is larger than the sum of its proper divisors (1).
122441131003 is an equidigital number, since it uses as much as digits as its factorization.
122441131003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 122441131003 its reverse (300131144221), we get a palindrome (422572275224).
The spelling of 122441131003 in words is "one hundred twenty-two billion, four hundred forty-one million, one hundred thirty-one thousand, three".
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