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1224431202103 = 3139497780713
BaseRepresentation
bin10001110100010101110…
…010010110111100110111
311100001110201022202202121
4101310111302112330313
5130030113341431403
62334255042020411
7154314355331344
oct21642562267467
94301421282677
101224431202103
1143230754690a
12179377647707
138b60402b805
144339712b7cb
1521cb49a53bd
hex11d15c96f37

1224431202103 has 4 divisors (see below), whose sum is σ = 1263928982848. Its totient is φ = 1184933421360.

The previous prime is 1224431202079. The next prime is 1224431202107. The reversal of 1224431202103 is 3012021344221.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1224431202103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1224431202107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19748890326 + ... + 19748890387.

It is an arithmetic number, because the mean of its divisors is an integer number (315982245712).

Almost surely, 21224431202103 is an apocalyptic number.

1224431202103 is a deficient number, since it is larger than the sum of its proper divisors (39497780745).

1224431202103 is an equidigital number, since it uses as much as digits as its factorization.

1224431202103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39497780744.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1224431202103 its reverse (3012021344221), we get a palindrome (4236452546324).

The spelling of 1224431202103 in words is "one trillion, two hundred twenty-four billion, four hundred thirty-one million, two hundred two thousand, one hundred three".

Divisors: 1 31 39497780713 1224431202103