Base | Representation |
---|---|
bin | 10001110100101100100… |
… | …101001001100000011111 |
3 | 11100002110100220100211020 |
4 | 101310230211021200133 |
5 | 130031404241141020 |
6 | 2334401022255223 |
7 | 154330010644215 |
oct | 21645445114037 |
9 | 4302410810736 |
10 | 1224813615135 |
11 | 43249339a440 |
12 | 179463727513 |
13 | 8b665323106 |
14 | 433d1c34cb5 |
15 | 21cd8342c40 |
hex | 11d2c94981f |
1224813615135 has 32 divisors (see below), whose sum is σ = 2138819696640. Its totient is φ = 593581468800.
The previous prime is 1224813615131. The next prime is 1224813615161. The reversal of 1224813615135 is 5315163184221.
It is not a de Polignac number, because 1224813615135 - 22 = 1224813615131 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1224813615131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1304655 + ... + 2037584.
It is an arithmetic number, because the mean of its divisors is an integer number (66838115520).
Almost surely, 21224813615135 is an apocalyptic number.
1224813615135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1224813615135 is a deficient number, since it is larger than the sum of its proper divisors (914006081505).
1224813615135 is a wasteful number, since it uses less digits than its factorization.
1224813615135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3344479.
The product of its digits is 172800, while the sum is 42.
Adding to 1224813615135 its reverse (5315163184221), we get a palindrome (6539976799356).
The spelling of 1224813615135 in words is "one trillion, two hundred twenty-four billion, eight hundred thirteen million, six hundred fifteen thousand, one hundred thirty-five".
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