Base | Representation |
---|---|
bin | 1011001001001110110001… |
… | …0110010011111111010101 |
3 | 1121101101200102010110212120 |
4 | 2302103230112103333111 |
5 | 3101224034233001323 |
6 | 42021014202010153 |
7 | 2403160005342252 |
oct | 262235426237725 |
9 | 47341612113776 |
10 | 12253212000213 |
11 | 39a4615808388 |
12 | 145a907aa6959 |
13 | 6ab61c05c402 |
14 | 3050b6c20429 |
15 | 163b02c085e3 |
hex | b24ec593fd5 |
12253212000213 has 8 divisors (see below), whose sum is σ = 16561418959488. Its totient is φ = 8056906520544.
The previous prime is 12253212000167. The next prime is 12253212000217. The reversal of 12253212000213 is 31200021235221.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12253212000213 - 28 = 12253211999957 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12253212000217) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27975369645 + ... + 27975370082.
It is an arithmetic number, because the mean of its divisors is an integer number (2070177369936).
Almost surely, 212253212000213 is an apocalyptic number.
It is an amenable number.
12253212000213 is a deficient number, since it is larger than the sum of its proper divisors (4308206959275).
12253212000213 is an equidigital number, since it uses as much as digits as its factorization.
12253212000213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55950739803.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 12253212000213 its reverse (31200021235221), we get a palindrome (43453233235434).
The spelling of 12253212000213 in words is "twelve trillion, two hundred fifty-three billion, two hundred twelve million, two hundred thirteen", and thus it is an aban number.
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