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1225335103051 is a prime number
BaseRepresentation
bin10001110101001011101…
…010011101111001001011
311100010210201011200202111
4101311023222131321023
5130033441241244201
62334524451443151
7154345642345153
oct21651352357113
94303721150674
101225335103051
114327307a2a94
1217958a2b64b7
138b71938c947
14434411c1763
1521d19002b51
hex11d4ba9de4b

1225335103051 has 2 divisors, whose sum is σ = 1225335103052. Its totient is φ = 1225335103050.

The previous prime is 1225335103001. The next prime is 1225335103067. The reversal of 1225335103051 is 1503015335221.

It is a strong prime.

It is an emirp because it is prime and its reverse (1503015335221) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1225335103051 - 215 = 1225335070283 is a prime.

It is a super-2 number, since 2×12253351030512 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1225335103001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 612667551525 + 612667551526.

It is an arithmetic number, because the mean of its divisors is an integer number (612667551526).

Almost surely, 21225335103051 is an apocalyptic number.

1225335103051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1225335103051 is an equidigital number, since it uses as much as digits as its factorization.

1225335103051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 31.

The spelling of 1225335103051 in words is "one trillion, two hundred twenty-five billion, three hundred thirty-five million, one hundred three thousand, fifty-one".